APTITUDE TEST SOLUTION 1

1.King : Throne : : Rider : ?

(A)Seat (B)Horse (C)Saddle (D)Chair

Ans: (C)

Explanation: A king sits on throne and a rider on a saddle .

2.Taxonomy:Classification::Pedology:?

(a)Nature(b)Farming(c)Soil(d)Mountain

Ans:(c)

Exp:Taxonomy is the science dealing with classification. Similarly,pedology deals with study of soils.

3.Winter : Hibernation : : Summer : ?

(a)Survival (b)Activation (c)Aestivation (d)Cache

Ans: (c)

Exp: Winter sleep of animals is called hibernation and summer sleep is called aestivation.

4. Foresight : Anticipation : : Insomnia : ?

(a)Diamond (b)Iron (c)Sleeplessness (d)Gems

Ans: (c)

Exp: The words in each pair are synonyms.

ODD MAN OUT SERIES

5 a.Lion:roar b. snake:hiss

c. bees:hum d. frog:bleat

Ans: (d)

Explanation:

In all other pairs second one is the noise produced by the

first.

6 a.beans:pluse b. rice:cereals

c.tea:beverage: d.legumes:nodules

Ans: (d)

Explanation:

In all other pairs ,second denotes the the class to which the

first belongs.

7. a. Abominable b.tempestuous

c.abhorrent d.detestable

Ans: (b)

Explanation:

tempestuous = resembling pertaining to violent storm. All other are related to hateful.

8. a. reprimand b. dissipate

c. chastise d. castigate

Ans: (b)

Explanation:

dissipate = to scatter, to dispel . All other words are related to criticism.

9 A) Cathedral B) Mosque C) Church D) Monastery E) Temple

Ans:- (D)

Exp:- Here all except Monastery are places of worship, While monastery is a place where monks stay

10. A) Epicentre B) Sesimology C) Focus D) Crater E) Richter Scale

Ans:- (C) Exp:- All except Crater are the terms related to the Earth Quakes.

11)Two pipes A& B can fill a tank in 36 hours and 45 hours respectively. If both the pipes are opened simultaneously, how much time will be taken to fill the tank? 

Sol: Part filled by A in 1 hour=1/36 

Part filled by B in 1 hour= 1/45; 

Part filled by (A+B)'s in 1 hour=1/36 +1/45= 9/180 =1/20 

Hence, both the pipes together will fill the tank in 20 hours. 

12)Two pipes can fill a tank in 10 hours & 12 hours respectively. While 3rd pipe empties the full tank n 20 hours. If all the three pipes operate simultaneously,in how much time will the tank be filled?

 Sol: Net part filled in 1 hour=1/10 +1/12 -1/20 =8/60=2/15

 The tank be filled in 15/2hours= 7 hrs 30 min

13)A leak in the bottom of a tank can empty the full tan in 8 hr. An inlet pipe fills water at the rate of 6 lits a minute. When the tank is full, the inlet is opened and due to the leak, the tank is empty in 12 hrs. How many liters does the cistern hold? 

 Sol: Work done by the inlet in 1 hr= 1/8 -1/12=1/24 Work done by the inlet in i min= (1/24)*(1/60)=1/1440 Therefore, Volume of 1/1440 part=6 lit Volume of whole=(1440*6) lit=8640 lit. 

14)Two pipes A and B can fill a cistern in 37 ½ min and 45 minutes respectively. Both the pipes are opened. The cistern will be filled in just half an hour, if the pipe B is turned off after: 

sol: Let B be turned off after x min. 

Then, Part filled by (A+B) in x min+ part filled by A in (30-x)min=1 

Therefore, x(2/75+1/45)+(30-x)(2/75)=1 11x/225 + (60-2x)/75=1 11x+ 180-6x=225 x=9.

 So, B must be turned off after 9 minutes.

 15)A train M leaves Meerat at 5 am and reaches Delhi at 9am . Another train N leaves Delhi at 7am and reaches Meerut at 1030am At what time do the 2 trains cross one another 

Solution:: Let the distance between Meerut & Delhi be x they meet after y hr

 after 7am M covers x in 4hr N covers x in 3 ½ i.e 7/2 hr

 speed of M =x/4 

speed of N = 2x/7

 Distance covered by M in y+2 hr + Distance covered by N in y hr is x x/4 (y+2) +2x/7(y)=x y=14/15hr or 56 min 

16)A man takes 5hr 45min in walking to certain place and riding back. He would have gained 2hrs by riding both ways.The time he would take to walk both ways is? 

Solution:: Let x be the speed of walked Let y be the speed of ride Let D be the distance 

Then D/x + D/y = 23/4 hr -------1

 D/y + D/y = 23/4 – 2 hr D/y = 15/8 --------2 

substitute 2 in 1 D/x + 15/8 = 23/4 D/x = 23/4 -15/8 =46-15/8 =31/8 

Time taken for walk one way is 31/8 hr 

time taken to walk to and fro is 2*31/8 = 31/4 hr =7 hr 45 min

 

17. In what ratio must rice at Rs 9.30 per Kg be mixed with rice at Rs 10.80 per Kg so that the mixture be worth Rs 10 per Kg?

 Solution: C.P of 1 Kg rice of 1st kind 930 p C.P of 1 Kg rice of 2nd kind 1080p Mean Price 1000p 80 70 Required ratio=80:70 = 8:7 

 18.How much water must be added to 60 liters of milk at 11/2 liters for Rs 20 so as to have a mixture worth Rs 10 2/3 a liter? 

Solution: C.P of 1 lit of milk = 20*2/3 = 40/3 C.P of 1 lit of water 0 C.P of 1 lit of milk 40/3 

Mean Price 32/3 8/3 32/3 Ratio of water and milk =8/3 : 32/3 = 1:4 

Quantity of water to be added to 60 lit of milk=1/4*60=15 liters.

19One side of a rectangular field is 15m and one of its diagonal is 17m. Find the area of field? 

Sol:Other side = √[(17*17) – (15*15)] = √(289-225) = 8m Area = 15 * 8 =120 sq. m

 20.A lawn is in the form of a rectangle having its sides in the ratio 2:3 The area of the lawn is 1/6 hectares. Find the length and breadth of the lawn. 

Sol: let length = 2x meters and breadth = 3x mt Now area = (1/6 * 1000)sq m = 5000/3 sq m 2x * 3x = 5000/3 =>x * x =2500 / 9 x = 50/3 length = 2x = 100/3 m and breadth = 3x = 3*(50/3) = 50m 

21.Find the cost of carpeting a room 13m long and 9m broad with a carpet 75cm wide at the rate of Rs 12.40 per sq meter

 Sol: Area of the carpet = Area of the room = 13* 9 =117 sq m length of the carpet = (Area/width) = 117 * (4/3) = 156 m Cost of carpeting = Rs (156 * 12.40) = Rs 1934.40 

22.The length of a rectangle is twice its breadth if its length is decreased by 5cm and breadth is increased by 5cm, the area of the rectangle is increased by 75 sq cm. Find the length of the rectangle. 

Sol: let length = 2x and breadth = x then (2x-5) (x+5) – (2x*x)=75 5x-25 = 75 => x=20

length of the rectangle = 40 cm

23.In one hour a boat goes 11 km long the stream and 5 km against the stream. The speed of the boat in still water is?

 Sol: Speed in still water = ½ ( 11+5) km/hr= 8 kmph 

24.A man can row 18 kmph in still water. It takes him thrice as long as row up as to row down the river. find the rate of stream. 

Sol: Let man's rate up stream be xkmph then, in still water =1/2[3x+x]=2x kmph so, 2x= 18, x=9 rate upstream =9kmph rate downstream =27 kmph rate of stream = ½ [27-9] = 9kmph 

25.At his usual rowing rate, Rahul 12 miles down stream in a certain river in 6 hrs less than it takes him to travel the same distence upstream. but if he could double his usual rowing rate for his 24 miles roundthe down stream 12 miles would then take only one hour less than the up stream 12 miles. what is the speed of the current in miles per hours? 

Sol: Let the speed in still water be x mph and the speed of the current be y mph.

 then, speed upstream = (x-y) 

speed downstream =(x+y) 12/(x-y) - 12/(x+y) = 6 6(x2 – y2) m= 2xy => x2 – y2 =4y -(1) and 12/(2x-y) - 12/(2x+y) =1 => 4x2 – y2 = 24y x2= ( 24y + y2)/4 -->(2) 

 from 1 and 2 we have 4y+ y2 =( 24y+y2)/4 y=8/3 mph y= 22/3 mph